方法一:不需要权限(推荐)
使用一些不需要权限的硬件设备码来生成Android设备的唯一识别码
//获得独一无二的Psuedo ID
public static String getUniquePsuedoID() {
String serial = null;
String m_szDevIDShort = "35" +
Build.BOARD.length()%10+ Build.BRAND.length()%10 +
Build.CPU_ABI.length()%10 + Build.DEVICE.length()%10 +
Build.DISPLAY.length()%10 + Build.HOST.length()%10 +
Build.ID.length()%10 + Build.MANUFACTURER.length()%10 +
Build.MODEL.length()%10 + Build.PRODUCT.length()%10 +
Build.TAGS.length()%10 + Build.TYPE.length()%10 +
Build.USER.length()%10 ; //13 位
try {
serial = android.os.Build.class.getField("SERIAL").get(null).toString();
//API>=9 使用serial号
return new UUID(m_szDevIDShort.hashCode(), serial.hashCode()).toString();
} catch (Exception exception) {
//serial需要一个初始化
serial = "serial"; // 随便一个初始化
}
//使用硬件信息拼凑出来的15位号码
return new UUID(m_szDevIDShort.hashCode(), serial.hashCode()).toString();
}
方法二:在接受需要用户授权的情况下生成唯一识别码:
需要添加权限,当然也需要做动态权限适配。
<uses-permission android.permission.READ_PHONE_STATE/>
方法如下:
public static String getAPPID(){
final TelephonyManager tm = (TelephonyManager) MyApplication.getContext().getSystemService(Context.TELEPHONY_SERVICE);
final String tmDevice, tmSerial, androidId;
tmDevice = "" + tm.getDeviceId();
tmSerial = "" + tm.getSimSerialNumber();
androidId = "" + android.provider.Settings.Secure.getString(MyApplication.getContext().getContentResolver(), android.provider.Settings.Secure.ANDROID_ID);
UUID deviceUuid = new UUID(androidId.hashCode(), ((long)tmDevice.hashCode() << 32) | tmSerial.hashCode());
return deviceUuid.toString();
}